InterviewSolution
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The value of [(a-b)(b-c)(c-a)] is equal to |
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Answer» 0 `= (a-b).[(b-c) XX (c-a)]` `= (a-b).[bxxc-bxxa-cxxc+cxxa]` `= (a-b).[bxxc-bxxa+cxxa] ""[ :' c xx c = 0]` `= a.[bxxc]- a.[bxxa] + a.[cxxa] - b.[bxxc]+b.[bxxa] - b.[cxxa]` `= [abc] - 0 + 0 + 0 - [BCA]` `= [abc] - [abc] = 0` |
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