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The value of [a-b b-c c-a] is equal to

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Solution :`[(a-b,b-C,c-a)]`
`={(a-b)XX(b-c)}.(c-a)`
`=(AXXB-axxc-bxxb+bxxc).(c-a)`
`=(axxb+cxxa+bxxc).(c-a)`
`=(axxb).c-(bxxc).a`
`=[ABC]-[abc]=0`


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