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The value of a cylinder containing initially 10L of an ideal gas at 25 atm and 25^(@)C is opened to the atmosphere, where the pressure is 760 torr and the temperature is 25^(@)C. Assuming that the process is isothermal the work in L-atm in the process is: |
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Answer» 240 L ATM `n_(1) = (25 xx 10)/(RT), n_(2) = (1 xx 10)/(RT)` moles LOST `= (24 xx 10)/(RT)` Volume occupied by these moles `=(24 xx 10)/(RT) xx RT = 240L` `:. V_(2) = 10 + 240= 250L` `rArr W = -1 xx (250-10) = - 240 L`-atm |
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