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The value of a such that x2 - 11x +a = 0 and x2 -14x +2a = 0 may have a common root is A. 0 B. 12 C. 24 D. 32 |
Answer» Subtracting both the equations we get, x2 – 11x + a - x2 +14x + 2a = 0 3x – a = 0 x = \(\frac{a}{3}\) Substituting it in first equation we get, \(\Big(\frac{a}{3}\Big)^2\) - 11 \(\frac{a}{3}\) + a = 0 \(\frac{a^2}{9}\) - \(\frac{8a}{3}\) = 0 a2 - 24a = 0 a = 24 |
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