1.

The value of bond enthalpy of H_(2) , CI_(2) and HCI are 104, 58 and 103 kilogram respectively. Than find the enthalpy of formation of HCI_((g)). reaction:(1)/(2) H_(2(g)) + (1)/(2) CI_(2(g)) to HCI_((g))

Answer»

SOLUTION :`-22` kj/mol


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