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the value of c, if the points (2, 0) (0, 1) (4, 5) (0, c) are concyclic.Oo |
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Answer» First find the equation of circle passes through point(2,0) ,(0,1) and (4,5)equation of the circlex² +y² +2gx +2fy +c =0so put the points4+ 4g +c =0 .............11 +2f +c =0 ..............239 + 8g + 10f +c =0 ............3solve these equationg =-25/12f =-8/3c =13/3so equation of circlex² + y² -25x/6 -16y/3 +13/3 =0now point(0,c) satisfy this equationc2 -16c/3 + 13/3 =03c2 -16c +13 =0c=1 ,13/3 Like my answer if you find it useful! |
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