The value of Cp - Cv = 1.00 R for a gas in state A and Cp - Cp =

1.	The value of Cp - Cv = 1.00 R for a gas in state A and Cp - Cp = 1.06 R in The value of PA and PB denote the pressure and TA and TB denote the temperatures in the two states, then(a) PA = PB , TA > TB(b) PA > PB , TA = TB(c) PA < PB , TA > TB(d) PA > PB , TA < TB
Answer» Correct Option (c) P_A < P_B , T_A > T_B Explanation: For state A, C_p - C_v = R i.e. the gas behaves as ideal gas. For state B, C_p - C_v = 1.06 R (≠ R) i.e. the gas does not behave like ideal gas. and we know that at high temperature and at low pressure nature of gas may be ideal. So we can say that (c) P_A < P_B and T_A > T_B

The value of Cp - Cv = 1.00 R for a gas in state A and Cp - Cp = 1.06 R in The value of PA and PB denote the pressure and TA and TB denote the temperatures in the two states, then(a) PA = PB , TA > TB(b) PA > PB , TA = TB(c) PA < PB , TA > TB(d) PA > PB , TA < TB

Answer»

Correct Option (c) P_A < P_B , T_A > T_B

Explanation:

For state A, C_p - C_v = R i.e. the gas behaves as ideal gas.

For state B, C_p - C_v = 1.06 R (≠ R) i.e. the gas does not behave like ideal gas.

and we know that at high temperature and at low pressure nature of gas may be ideal. So we can say that (c) P_A < P_B and T_A > T_B