1.

The value of Delta_f G^@ for the formation of Cr_2 O_3 is -540 KJ mol^(-1) and that of Al_2 O_3 is -827 KJ mol^(-1). Is reduction of Cr_2 O_3 possible with Al ?

Answer»

Solution :The TWO EQUATIONS are :
`(i) 4/3 Al (s) + O_2 (g) to 2/3 Al_2 O_3 (s)Delta_f G^@ (Al, Al_2 O_3) = -827 KJ mol^(-1)`
(ii) `4/3 Cr (s) + O_2 (g) to 2/3 Cr_2 O_3 (s) ""Delta_f G^@ (Cr, Cr_2 O_3) =-540 KJ mol^(-1)`
SUBTRACTING eqn. (ii) from eqn (i), we get
`4/3 Al (s)+ 2/3 Cr_2 O_3 (s) to 2/3 Al_2 O_3 (s) + 4/3 Cr(s) "" Delta_r G^@ =-287 KJ mol^(-1)`
Since `Delta_r G^@` for the combined REACTION is -ve. therefore , the above reaction, i.e. reduction of `Cr_2 O_3` by Al is POSSIBLE.


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