Saved Bookmarks
| 1. |
The value of Delta G^(@) for the phosphorylation of glucose in glucolysis is13*8kj//mol. Find the value of K_(c) at 298 K. |
|
Answer» Solution :`DELTAG^(@) = 13*8 " Kjmol"^(-1)= 13*8 xx 10^(3)" J mol"^(-1)` `Delta G^(@) = - 2*303" RT "log K_(c)` `13*8 xx 10^(3) "J mol"^(-1) = -2*303 xx ( 8*314 " JK"^(-1)" mol"^(-1))(298 K) " log "K_(c)or log K_(c) = -2*4186 = bar(3)*5814` `K_(c) = " ANTILOG " (bar(3)*5814) = 3*815 xx 10^(-3)` |
|