1.

The value of DeltaG ((KJmol^(-1)) for the given cell is : ( Taken 1F = 96500C mol^(-1)

Answer»

`(-5.7)`
`(5.7)`
`(11.4)`
`(-11.4)`

SOLUTION :`DeltaG=-nFE=-2xx96500xx0.059=-11.4 kJ//m OL `


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