The value of DeltaG^ө for the phosphorylation of glucose in glycolysis is 13.8 kJ/mol. Find the value of K_c at 298 K.

The value of DeltaG^ө for the phosphorylation of glucose in glycolysi

1.	The value of DeltaG^ө for the phosphorylation of glucose in glycolysis is 13.8 kJ/mol. Find the value of K_c at 298 K.
Answer» Solution :`DeltaG^ө`=13.8 kJ `mol^(-1)= (13.8xx10^3) "J mol"^(-1)` `DeltaG^ө=-RT ln K_c` `therefore DeltaG^ө`=-2.303 RT LOG `K_c` `therefore log_10 K_c=-(DeltaG^ө)/(2.303RT)` `=-(13.8xx10^3 "J mol"^(-1))/((2.303)xx(8.314 "J mol"^(-1) K^(-1))xx(298 K))` =-2.4186=`bar3.5814` `therefore K_c`=Antilog `bar3.5814=3.814xx10^(-3)`