1.

The value of DeltaH for cooling 2 moles of an ideal monoatomic gas from 125^@ Cto 25^@ C at constant pressure will be [given C_p = 5/2 R] ………………. .

Answer»

`-250 R`
`-500 R`
500 R
`+250 R`

Solution :`T_(i) = 125^(@)C=398K`
`T_(f)=25^(@)C = 298K`
`DeltaH = nC_(P)(T_(i)-T_(f))`
`DeltaaH =2XX(5)/(2)R(298-398)`
`DeltaH =-500R`


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