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The value of DeltaH for cooling 2 moles of an ideal monoatomic gas from 125^@ Cto 25^@ C at constant pressure will be [given C_p = 5/2 R] ………………. . |
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Answer» `-250 R` `T_(f)=25^(@)C = 298K` `DeltaH = nC_(P)(T_(i)-T_(f))` `DeltaaH =2XX(5)/(2)R(298-398)` `DeltaH =-500R` |
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