1.

The value of `(E_(H_(2)O)//H_(2)^(@))` (1atm) Pt at 298K would b eA. `+0.207`B. `-0.414V`C. `-0.207V`D. `+0.414V`

Answer» Correct Answer - B
For pure water `[H^(+)]=10^(-7)M`
`H^(+)(aq)+e^(-)rarr1//2H_(2)`
`E=E^(@)-(0.0591V)/(1)"log "(1)/([H^(+)])`
`=0V-(0.0591V)/(1)"log"(1)/(10^(-7))`
`=-0.0591Vxx"log"10^(7)`
`=-0. 0591xx7V=-0.414V`


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