1.

The value of enthalpy change (Delta H) for the reaction : C_(2)H_(5)OH(l) + 3O_(2)(g) rarr 2CO_(2)(g) + 3H_(2)O(l) at 27^(@)C is - 1366.5 kJ mol^(-1). The value of internal energy change for the above reaction at the temperature will be :

Answer»

`- 1369.0 kJ`
`- 1364.0 kJ`
`- 1361.5 kJ`
`- 1371.5 kJ`

Solution :`DELTA H = Delta U + Delta n_(g) RT`
or `Delta U = Delta H + Delta n_(g) RT`
`Delta n_(g) = 2 - 3 = -1`
:. `Delta U = - 1366.5 - (- 1) xx 8.3 xx 10^(-3) xx 300`
`= - 1366.5 + 2.490 = - 1364.01 kJ`


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