1.

The value of enthalpy change (DeltaH) for the reaction C_(2)H_(5)OH(l)+3O_(2)(g)to2CO_(2)(g)+3H_(2)O(l), at 27^(@)C is -1366.5" kJ "mol^(-1). The value of internal energy change for the above reaction at this temperature will be

Answer»

`-1371.5kJ`
`-1369.0kJ`
`-1364.5kJ`
`-1361.5kJ`

Solution :`DeltaH=DeltaE+Deltan_(g)RT`
where, `Deltan_(g)=`NUMBER of moles of gaseous products-no. of moles of gaseous reactants
=2-3=-1
`implies -1365.5=DeltaE-1xx8.314xx10^(-3)xx300`
`DeltaE=-1364.0" KJ "mol^(-1)`


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