The value of equilibrium constant of reaction HI_((g))hArr1/2H_(2(g))+1/2I_(2(g)) is 8.0. The equilibrium constant of the reaction , H_(2(g))+I_(2(g))hArr2HI_((g)) will be

The value of equilibrium constant of reaction HI_((g))hArr1/2H_(2(g))+

1.	The value of equilibrium constant of reaction HI_((g))hArr1/2H_(2(g))+1/2I_(2(g)) is 8.0. The equilibrium constant of the reaction , H_(2(g))+I_(2(g))hArr2HI_((g)) will be
Answer» `1/8` `1/16` `16` `1/64` Solution :FORMATION `ALPHA(1)/("DISSOCIATION")` Then when the reactants & products CONCENTRATION are doubled, hence equilibrium constant is also doubled.