1.

The value of f(0), so that the function f(x)=((27-2x)^(1//3)-3)/(9-3(243+5x)^(1//5)),(xne0) is continuous at x=0, is given by

Answer»

`(2)/(3)`
`6`
`2`
`4`

Solution :Since f (x) is CONTINUOUS at x = 0, THEREFORE
`f(0) = underset(xrarr0)lim f (x) = underset(xrarr0)lim ((27-2x)^(1//3)-3)/(9-3(243+5x)^(1//5))`
`("from"(0)/(0))`
`=underset(xrarr0)lim((1)/(3)(27-2x)^(-2//3)(-2))/(-(3)/(5)(243+_5x)^(-4//5)(5))=2`


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