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The value of `f(0)`, so that the function `f(x)=((27-2x)^(1//3)-3)/(9-3(243+5x)^(1//5)),(xne0)` is continuous at `x=0`, is given byA. `(2)/(3)`B. `6`C. `2`D. `4` |
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Answer» Correct Answer - C Since f (x) is continuous at x = 0, therefore `f(0) = underset(xrarr0)lim f (x) = underset(xrarr0)lim ((27-2x)^(1//3)-3)/(9-3(243+5x)^(1//5))` `("from"(0)/(0))` `=underset(xrarr0)lim((1)/(3)(27-2x)^(-2//3)(-2))/(-(3)/(5)(243+_5x)^(-4//5)(5))=2` |
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