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The value of four quantum number for the last electron of atom of element x are n = 7, l = 1 and `m = +1` and `s=+1//2" or "-1//2` and magnetic moment of element x is zero. The incorrect statement regarding element x isA. Element x belongs to `16^(th)` group.B. Atomic number of x is 118C. Element x belongs to `18^(th)` group.D. Eight electrons are present in valence shell.

Answer» Correct Answer - C
x is `As rarr[Ar] 3d^(10)4s^(2)4p^(3)`
`2|s|+1=4" "|s|=3//2`
So, unpaired electron in electronic element x is 3.


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