InterviewSolution
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InterviewSolution
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The value of `IE_(1), IE_(2), IE_(3)` and `IE_(4)` of an atom are respectively `7.5 eV, 25.6 eV, 48.6 eV` and `170.6 eV`. The electronic configuration of the atom will beA. `1s^(2), 2s^(2)2p^(6), 3s^(1)`B. `1s^(2)2s^(2)2p^(6)3s^(2) 3p^(1)`C. `1s^(2), 2s^(2)2p^(6)3s^(2)3p^(3)`D. `1s^(2), 2s^(2)2p^(6)3s^(2)` |
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Answer» Correct Answer - B There is a high jump from `IE_(3)` to `IE_(4)`. Therefore, it is difficult to remove the 4th valence electron. So, electronic configuration of element must have three valence electrons. Hence, the answer is (b). |
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