1.

The value of `int("cosec x")/(cos^(2)(1+logtan.(x)/(2)))dx` isA. `-tan(1+logtan.(x)/(2))+c`B. `sec^(2)(1+logtan.(x)/(2))+c`C. `tan(1+log tan.(x)/(2))+c`D. `sin^(2)(1+logtan.(x)/(2))+c`

Answer» Correct Answer - C
`I=int("cosec x")/((cos^2)(1+log tan.(x)/(2)))dx`
`"Let "1+log tan.(x)/(2)=t`
`therefore" "(1)/(sin x)dx=dt`
`therefore" "I=int(dt)/(cos^(2)t)`
`" "=tant+c`
`" "=tan(1+log tan.(x)/(2))+c`


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