The value of K_(c) for the reaction, 2 HI (g) hArr H_(2)g + I_(2) (g)is 1xx10^(-4) At a given time, the composition of reaction mixture is [HI] = 2xx10^(-5) "mol"and [I_(2)]=1xx10^(-5)mol In which direction will the reaction proceed ?

The value of K_(c) for the reaction, 2 HI (g) hArr H_(2)g + I_(2) (g)

1.	The value of K_(c) for the reaction, 2 HI (g) hArr H_(2)g + I_(2) (g)is 1xx10^(-4) At a given time, the composition of reaction mixture is [HI] = 2xx10^(-5) "mol"and [I_(2)]=1xx10^(-5)mol In which direction will the reaction proceed ?
Answer» Solution :REACTION quotient (Q) `= ([H_(2)][I_(2)])/([HI]^(2))=((10^(-5))(10^(-5)))/((2xx10^(-5))^(2))=(1)/(4) = 0.25 =2.5xx10^(-1)` As `Q gt K_(c)`, the reaction will proceed in the reverse direction.