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The value of K_c for the reaction 2A hArr B+ C is 2 xx 10^(-3). At a given time, the composition of reaction mixture is [A] = [B] = [C] = 3 xx 10^(-4) M. In which direction the reaction will proceed ? |
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Answer» Solution :`{:("Reaction :",2A HARR, B+, C),("Concentration at t TIME :",3xx10^(-4), 3xx10^(-4), 3xx10^(-4)):}` At t time the reaction quotient, `Q_c=([B][C])/[A]^2=((3xx10^(-4))(3xx10^(-4)))/(3xx10^(-4))^2-1.0` Thus, `(Q_c=1.0) gt (K_c=2xx10^(-3))` Here, value of `Q_c gt K_c`, So the reaction will proceed in the DIRECTION of reactant (reverse reaction). The reactant converted into reactant till`Q=2xx10^(-3)`. |
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