The value of K_c for the reaction 2HI_((g)) hArr H_(2(g)) + I_(2(g)) is 1xx10^(-4) At a given time, the composition of reaction mixture is (HI] = 2 xx 10^(-5) mol, [H_2] = 1 xx 10^(-5) mol and [I_2] = 1 xx 10^(-5) mol In which direction will the reaction proceed ?

The value of K_c for the reaction 2HI_((g)) hArr H_(2(g)) + I_(2(g))

1.	The value of K_c for the reaction 2HI_((g)) hArr H_(2(g)) + I_(2(g)) is 1xx10^(-4) At a given time, the composition of reaction mixture is (HI] = 2 xx 10^(-5) mol, [H_2] = 1 xx 10^(-5) mol and [I_2] = 1 xx 10^(-5) mol In which direction will the reaction proceed ?
Answer» Solution :Given for , `[HI]=2xx10^(-5)` mol `[H_2] = 1xx10^(-5)` mol `[I_2]= 1xx10^(-5)` mol At a given TIME, the reaction quotient Q for the reaction will be given by the expression `Q=([H_2][I_2])/[HI]^2` `=(1xx10^(-5) xx 1xx10^(-5))/(2xx10^(-5))^2=1/4=0.25 =2.5xx10^(-1)` If the value of reaction quotient is more than the value of `K_c`.i.e., `1 xx 10^(-4)` the reaction will PROCEED in the reverse reaction.