The value of K_c for the reaction 3O_(2(g)) hArr 2O_(3(g))is 2.0 xx10^(-50) at 25^@C. If the equilibrium concentration of O_2 in air at 25^@C is 1.6 xx 10^(-2), what is the concentration of O_3 ?

The value of K_c for the reaction 3O_(2(g)) hArr 2O_(3(g))is 2.0 xx10^

1.	The value of K_c for the reaction 3O_(2(g)) hArr 2O_(3(g))is 2.0 xx10^(-50) at 25^@C. If the equilibrium concentration of O_2 in air at 25^@C is 1.6 xx 10^(-2), what is the concentration of O_3 ?
Answer» Solution :`{:("Equilibrium reaction :",3O_(2(g)) hArr, 2O_(3(g))),("Constant of equilibrium :", 1.6xx10^(-2) , x):}` According to chemical equilibrium : `K_c=[O_3]^2/[O_2]^3` where, `K_c=2.0xx10^(-50)` `therefore 2.0xx10^(-50) = [O_3]^2/[1.6xx10^(-2)]^3` `[O_2]=1.6xx10^(-2)` `therefore [O_3]^2=2.0xx10^(-50) (1.6xx10^(-2))^3=8.192xx10^(-56)` `therefore [O_3]=(8.192xx10^(-56))^(1/2)` `=2.862xx10^(-28) "MOL L"^(-1)`