1.

The value of K_c for the reaction 3O_(2)(g) is 2.0 xx 10^(-50) and 25^(@)C . If equilbrium concentration of O_(2) in 25^(@)C is 1.6 xx 10^(-2) . What is the concentration of O_(3) ?

Answer»

Solution :`3O_(2)(g) hArrr 2O_(3)(g)`
`K_(c) = ([O]^2)/([O_2]^3) or (2.0 XX 10^(-50)) = ([O_3]^2)/(1.6 xx 10^(-2))^3`
or`[O_3]^2 = (2.0 xx 10^(-50)) xx (1.6 10^(-2))^3`
`[O_3]^2 =(8.192 xx 10^(-56))^(1//2) = 2.86 xx 10^(-28) M`


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