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The value of K for which the system of equation Kx+2y-y=0 and 2x+4y-12=0 have no solution, is ---(a) 1 (b) 2 (c) 3 (d) 0 |
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Answer» x − 3y − 3 = 0, x − 3y − 3 = 3x − 9y − 2 = 0, 3x − 9y − 2 = 0 Solution: The GIVEN system may be written as x − 3y − 3 = 0 3x − 9y − 2 = 0 The given system of equation is of the form A2X + b2y − c2 = 0 a2x + b2y − c2 = 0 Where, a1 = 1, b1 = −3, C1 = −3 a2 = 3, b2 = −9, c2 = −2 We have, THEREFORE, the given equation has no solution. so the answer is option d) 0 |
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