InterviewSolution
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InterviewSolution
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The value of ` K_(p) " for the reaction ", CO_(2) (g) + C (s) hArr 2 CO (g),` is 3.0 at 1000 K. Initially `, p_(co_(2)) = 0.48" bar "and P_(CO)= 0` bar and opure graphite is present , calculate the equilibrium partial pressures of `CO and CO_(2)` |
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Answer» `{:(,CO_(2)(g) + C(s),hArr,2 CO (g)),("Intial",0.48 " bar ",,0 "bar"),("AT.eqm.",(0.48-p)"bar",,2 " p bar"):}` ` K_(p) = (2 p)^(2)/(0.48-p )=3.0 " (Given) ".` ` :. 4 p^(2) = 1.44 - 3 p or 4 p^(2) + 3 p - 1.44=0` ` :. p = ( -b pm sqrt(b^(2) - 4 ac))/(2a)=(-3 pm sqrt ( 9-4 xx 4 ( - 1. 44)))/8` ` = ( -3 pm sqrt(32*04))/8= (-3 pm 5.66)/8 = 2.66/8 " "` (neglecting - ve value) = 0.33 atm `:. p_(CO_(2))= 0.48 - 0.33 = 0.15 " bar" , p_(CO_(2)) = 2 xx 0.33 = 0. 66 " bar " ` |
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