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The value of K_(sp) of two sparingly soluble salts Ni(OH)_2 and AgCN are 2.0 times 10^-15 and 6 times 10^-17 respectively. Which salt is more soluble ? Explain. |
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Answer» Solution :`AgCN leftrightarrow AG^(+)+ CN^-` `K_(sp)=[Ag^(+)][CN^(-)]=6 times 10^-17` `NI(OH)_2leftrightarrowNi^(2+)+2OH^-` `K_(sp)=[Ni^(2+)][OH^-]^2=2 times10^-15` Let `[Ag^+]=S_1,then[CN^-]=S_1` Let `[Ni^(2+)]=S_2, then[OH^-]=2S_2` `S_1^2=6times10^-17,S_1=7.8 times10^-9` `(S_2)(2S_2)^2=6times10^-17,S_1=0.58 times10^-4` `Ni(OH)_2` is more stable than AgCN. |
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