1.

The value of limn→∞⎡⎢⎢⎣1√(2n−12)+1√(4n−22)+1√(6n−32)+...+1n⎤⎥⎥⎦ is equal to

Answer»

The value of limn→∞⎡⎢
⎢
⎣
1√(2n−12)+1√(4n−22)+1√(6n−32)+...+1n⎤⎥
⎥
⎦
is equal to



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