1.

The value of limx→01x⎡⎢⎣a∫yesin2tdt−a∫x+yesin2tdt⎤⎥⎦ is equal to

Answer»

The value of limx→01x⎡⎢⎣a∫yesin2tdt−a∫x+yesin2tdt⎤⎥⎦ is equal to



Discussion

No Comment Found