1.

The value of log_(10)K for a reaction A hArr B is ( Given :Delta _(r) H_(298K)^(@)= -54.07kJmol^(-1),Delta_(r)S_(298K)^(@) = 10J K^(-1)mol^(-1) andR = 8.314 JK^(-1) mol^(-1), 2.303 xx 8.314 xx 298 K = 5705)

Answer»

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Solution :`DeltaG^(@) =DELTAH^(@) - T DELTA S^(@)= - 2.303 RT log _(10) K`
`:.-2.303 RT log_(10) K= DeltaH ^(@)- T DeltaS^(@)`
i.e., `-2.303 xx 8.314 xx 298 xx log_(10)K`
`=- 54.07xx 1000- 298 xx 10`
`-5705 log_(10)K =- 54070 - 2980 = - 57050`
or `log_(10)K =10`


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