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The value of ∫(logx)22xdx is (a) (logx)32+C (b) (logx)33+C(c) (logx)34+C (d) (logx)36+C |
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Answer» The value of ∫(logx)22xdx is (a) (logx)32+C (b) (logx)33+C(c) (logx)34+C (d) (logx)36+C |
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