1.

The value of (n_2 + n_1) and (n_2^2 - n_1^2) for He^+ ion in atomic spectrum are 4 and 8 respectively . The wavelength of emitted photon when electron jump from n_2to n_1is

Answer»

`(32)/(9) R_H`
`(9)/(32) R_H`
`(9)/(32) R_H)`
`(32)/(9) R_H)`

SOLUTION :`(n_2^2 - n_1^2)/(n_2 + n_1) = 8/4`
`IMPLIES((n_2 - n_1)(n_2 + n_1))/((n_2 + n_1)) = (n_2 + n_1) = 2`
`therefore n_2 = 3 , n_1 = 1 impliesbar(upsilon) = Z^2 R[1/(n_1^2)- 1/(n_2^2)]`
`=(2)^2 R (1/((1)^2) - 1/((3)^2))= (32R)/(9) , LAMBDA =(9)/(32R)`


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