1.

The value of n in the molecular formula Be_(1)Al_(2)Si_(6O_(18) is

Answer»

Solution :`FeS_(2)to2SO_(2)to2SO_(3)toH_(2)S_(2)O_(7)to2H_(2)SO_(4)`
1 mol of `FeS_(2)` = 2 mol of `H_(2)SO_(4) = 2 xx 98 gm H_(2)SO_(4)`
`therefore`Moles of `FeS_(2)=(5.52xx1000)/(120)`moles of `FeS_(2)=(5.52xx1000)/(120)xx298`
=9kg of `H_(2)SO_(4)`


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