1.

The value of n in the molecular formula Be_(n)I_(2)Si_(6)O_(18 is

Answer»


Solution :Since netcharge on the neutral molecule is zero therefore for the given molecule `Be_(N)"AII"_(2)Si_(6)O_(18)`
`n(+2)+2(+3)+6(+4)+18(-2)=0`
or 2n+6+24-36=0 or 2n=6
n=3


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