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The value of p, for which the points A(3, 1), B(5, p) and C(7, –5) are collinear, is (a) –2 (b) 2 (c) –1 (d) 1 |
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Answer» Since, points are collinear, then area of triangle formed by these points is zero. \(\frac{1}{2} |3(p+5)+5(-5-1)+7(1-p)|\) p = -2. |
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