1.

The value of Planck's constant is 6.63 xx 10^(-34)Js. The speed of light is 3xx 10^(17) nm s^(-1). Which value is closest to the wavelength in nanometer of a quantum of light with frequency of 6 xx 10^(15) s^(-1) ?

Answer»

10
25
50
75

Solution :`v = (C)/(LAMDA) or lamda = (c)/(v) = (3 xx 10^(17) nm s^(-1))/(6 xx 10^(15) X^(-1)) = 50 nm`


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