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The value of `PV` for `5.6 L` of an ideal gas is ……… `RT` at `NTP`.A. `0.25`B. `0.30`C. `1.0`D. `0.45` |
Answer» `V_(ideal)=22.4 L` `:. PV_(ideal)=(5.6)/(22.4)RT=0.25RT` |
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