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The value of resistance of an unknown resistor is calculated using the formula `R = V//I ` where V and I are the readings of the voltmeter and the ammeter, respectivley. Consider the circuits below. The internal resistances of the voltmeter and the ammeter `(R_V and R_G, respectively)` are finite and nonzero. , Let `R_(A) and R_(B)` be the calculated values in the two cases A and B , respectively. If the resistance of voltmeter is `R_(V) = 1k Omega` and the percentage error in the measurement of R (the value of R is nearly `10 Omega`)isA. zero in both casesB. nonzero but equal in both casesC. more in circuit AD. more in circuit B |
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Answer» Correct Answer - D d. `R_(A) = R_(A) = (R xx R_V)/(R+R_V) ltR` `R_(B) = R+R_0 gtR` (Tough) % error in case A. `(R_(A)-R)/R xx 100 = (R_(V)/(R+R_(V)) -1) xx 100 ` `R/(R+R_(V)) xx 100 = - 1%` Percentage error in case B `(R_(B) - R)/R xx 100 = R_(G)/R xx 100 = 10%` Hence, percentage error in circuit B is more than that in A. |
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