1.

The value of sec−1(1410∑k=0sec(7π12+kπ2)sec(7π12+(k+1)π2)) in the interval [−π4,3π4] equals

Answer» The value of sec1(1410k=0sec(7π12+kπ2)sec(7π12+(k+1)π2)) in the interval [π4,3π4] equals


Discussion

No Comment Found