1.

The value of sin2 θ + \(1\frac{1}{(1+tan^2θ)}\) is(1) sin2 θ(2) cos2 θ(3) Sec2 θ(4) 1

Answer»

 (4) 1

sinθ + \(\frac{1}{1+tan^2\theta}\) = sinθ + \(\frac{1}{sec^2\theta}\) = sinθ + cosθ = 1



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