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The value of \(\sqrt{3-2\sqrt2}\) isA. \(\sqrt3\) - \(\sqrt2\)B. \(\sqrt3\) + \(\sqrt2\)C. \(\sqrt5\) + \(\sqrt6\)D. none of these |
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Answer» \(\sqrt{3-2\sqrt2}\) √(√2)2+ 12 – 2 ×√2×1) = √(√2-1)2 = √2 – 1. |
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