1.

The value of \(\sqrt{3-2\sqrt2}\) isA. \(\sqrt3\) - \(\sqrt2\)B. \(\sqrt3\) + \(\sqrt2\)C. \(\sqrt5\) + \(\sqrt6\)D. none of these

Answer»

\(\sqrt{3-2\sqrt2}\)

(try to break the terms in form of (a+b)2 or (a – b )2)

√(√2)2+ 12 – 2 ×√2×1) = √(√2-1)2 = √2 – 1.



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