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The value of sqrt3cot20^(@)-4cos20^(@) is |
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Answer» `1` `=(sqrt(3)cos20^(@))/(sin20^(@))-4cos 20^(@)` `=(sqrt(3)COS 20^(@)-4sin20^(@)cos20^(@))/(sin20^(@))` `=(2[sqrt(3)/(2)cos 20^(@)-2sin20^(@)cos20^(@)])/(sin20^(@))` `=(2(SIN60^(@)cos20^(@)-sin40^(@)))/(sin20^(@))` `=([2sin60^(@)cos20^(@)-2sin40^(@)])/(sin20^(@))` ` =(sin80^(@)+sin40^(@)-2sin40^(@))/(sin20^(@))` `=(sin80^(@)-sin40^(@))/(sin20^(@))` `=(2cos60^(@).sin20^(@))/(sin20^(@))` `2xos60^(@)=1` |
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