1.

The value of tan−1√a(a+b+c)bc+tan−1√b(a+b+c)ca+tan−1√c(a+b+c)ab, where a,b,c>0, is

Answer»

The value of tan1a(a+b+c)bc+tan1b(a+b+c)ca+tan1c(a+b+c)ab, where a,b,c>0, is



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