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The value of tan-1\(\left(\cfrac{cos(\frac{15π}{4})-1}{sin(\frac{\pi}4)}\right)\) is equal to (A) -π/4 (B) -π/8 (C) -5π/12 (D) -4π/9 |
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Answer» Correct option is (B) -π/8 \(tan^{-1}[\cfrac{cos(4π-π/4)-1}{sinπ/4}]\) ⇒ tan-1\((\frac{cos π/4 - 1}{sin π/4})\) tan-1(\(\frac{1-√2}1\)) = \(-\frac{\pi}8\) |
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