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The value of tan-1(tan 5)(A) 2π(B) 5 - 2π(C) 5(D) \(\frac{2\pi}{3}\) |
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Answer» Answer is (B) Let 2π – 5 = θ, ⇒ 5 = 2π – θ tan 5 = tan (2π – θ) tan-1 (tan 5) = tan-1 tan (2π – θ) = tan-1 [-tan θ] = tan-1 [tan (-θ)] = – θ = – (2π – 5) = 5 – 2π |
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