The value of the specific heat at constant pressure for hydrogen is 3.4 kcal kg^(-1) ""^(@)C^(-1).Determine C_(V) for hydrogen if J = 4.2 J/cal. Density at NTP is 8.9 x 10^(-5) kg/litre. [E.Q]

The value of the specific heat at constant pressure for hydrogen is 3.

1.	The value of the specific heat at constant pressure for hydrogen is 3.4 kcal kg^(-1) ""^(@)C^(-1).Determine C_(V) for hydrogen if J = 4.2 J/cal. Density at NTP is 8.9 x 10^(-5) kg/litre. [E.Q]
Answer» Solution :`C _(p) = 3.4 K cal ^(-1) kg ^(-1) ""^(@)C ^(-1) = 3.4 xx 10 ^(3) cal ^(-1) kg ^(-1) l ^(@)C ^(-1) = 3.4 xx 10 ^(3) xx 4.2 J kg ^(-1) K ^(-1).` `C _(v) = ? C _(v) = C _(p) -R ` We have to find r `r = (PV)/(T), P = 101325 NM ^(-2), T = 273K` `V = ( " Mass ")/("DENSITY") , ` mass = 1 kg Density `= 8.9 xx 10 ^(-5) (kg)/("litre") = (8.9 xx 10 ^(-5))/(10 ^(-3)) (kg)/( m ^(3)) = 8.9 xx 10 ^(-2) kg//m^(3)` `V = (1)/( 8.9 xx 10 ^(-2)) m ^(3)` `r = (PV)/(T) = ( 101325)/(273) xx (1)/(8.9 xx 10^(-2)) = 4170J kg ^(-1) K ^(-1)` `C _(V) = 14280 -4170 = 10110 J kg ^(-1) K ^(-1)`