1.

The value of x which satisfies ∣∣∣∣x−22x−33x−4x−42x−93x−16x−82x−273x−64∣∣∣∣=0 is:

Answer» The value of x which satisfies ∣∣
∣
∣
x−22x−33x−4x−42x−93x−16x−82x−273x−64∣∣
∣
∣
=0
is:


Discussion

No Comment Found