The values of electronegativity of atoms A and B are 1.2 and 4.0 respectivity . The % ionic character of the A-B bond is

The values of electronegativity of atoms A and B are 1.2 and 4.0 respe

1.	The values of electronegativity of atoms A and B are 1.2 and 4.0 respectivity . The % ionic character of the A-B bond is
Answer» `50%` `72.24%` `55.3%` `43%` SOLUTION :ACCORDING to Hannay and Smith equation, % ionic character = `16 (chi_(A) - chi_(B)) + 3.5(chi_(A) - chi_(B))^(2)` ` 16 (4-0 - 1.2) + 3.5 (4 .0 - 1.2)^(2)` `= 16 xx2.8 + 3.5 xx (2.8)^(2)` `= 44.8 + 27 .44 = 72.24`